Optimal. Leaf size=244 \[ -\frac {3 b^2 e \log \left (\frac {2}{1-c x}\right ) \left (a+b \tanh ^{-1}(c x)\right )}{c^2}-\frac {3 b^2 d \text {Li}_2\left (1-\frac {2}{1-c x}\right ) \left (a+b \tanh ^{-1}(c x)\right )}{c}-\frac {\left (\frac {e^2}{c^2}+d^2\right ) \left (a+b \tanh ^{-1}(c x)\right )^3}{2 e}+\frac {3 b e \left (a+b \tanh ^{-1}(c x)\right )^2}{2 c^2}+\frac {(d+e x)^2 \left (a+b \tanh ^{-1}(c x)\right )^3}{2 e}+\frac {d \left (a+b \tanh ^{-1}(c x)\right )^3}{c}-\frac {3 b d \log \left (\frac {2}{1-c x}\right ) \left (a+b \tanh ^{-1}(c x)\right )^2}{c}+\frac {3 b e x \left (a+b \tanh ^{-1}(c x)\right )^2}{2 c}-\frac {3 b^3 e \text {Li}_2\left (1-\frac {2}{1-c x}\right )}{2 c^2}+\frac {3 b^3 d \text {Li}_3\left (1-\frac {2}{1-c x}\right )}{2 c} \]
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Rubi [A] time = 0.60, antiderivative size = 244, normalized size of antiderivative = 1.00, number of steps used = 14, number of rules used = 10, integrand size = 16, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.625, Rules used = {5928, 5910, 5984, 5918, 2402, 2315, 6048, 5948, 6058, 6610} \[ -\frac {3 b^2 d \text {PolyLog}\left (2,1-\frac {2}{1-c x}\right ) \left (a+b \tanh ^{-1}(c x)\right )}{c}-\frac {3 b^3 e \text {PolyLog}\left (2,1-\frac {2}{1-c x}\right )}{2 c^2}+\frac {3 b^3 d \text {PolyLog}\left (3,1-\frac {2}{1-c x}\right )}{2 c}-\frac {3 b^2 e \log \left (\frac {2}{1-c x}\right ) \left (a+b \tanh ^{-1}(c x)\right )}{c^2}-\frac {\left (\frac {e^2}{c^2}+d^2\right ) \left (a+b \tanh ^{-1}(c x)\right )^3}{2 e}+\frac {3 b e \left (a+b \tanh ^{-1}(c x)\right )^2}{2 c^2}+\frac {(d+e x)^2 \left (a+b \tanh ^{-1}(c x)\right )^3}{2 e}+\frac {d \left (a+b \tanh ^{-1}(c x)\right )^3}{c}-\frac {3 b d \log \left (\frac {2}{1-c x}\right ) \left (a+b \tanh ^{-1}(c x)\right )^2}{c}+\frac {3 b e x \left (a+b \tanh ^{-1}(c x)\right )^2}{2 c} \]
Antiderivative was successfully verified.
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Rule 2315
Rule 2402
Rule 5910
Rule 5918
Rule 5928
Rule 5948
Rule 5984
Rule 6048
Rule 6058
Rule 6610
Rubi steps
\begin {align*} \int (d+e x) \left (a+b \tanh ^{-1}(c x)\right )^3 \, dx &=\frac {(d+e x)^2 \left (a+b \tanh ^{-1}(c x)\right )^3}{2 e}-\frac {(3 b c) \int \left (-\frac {e^2 \left (a+b \tanh ^{-1}(c x)\right )^2}{c^2}+\frac {\left (c^2 d^2+e^2+2 c^2 d e x\right ) \left (a+b \tanh ^{-1}(c x)\right )^2}{c^2 \left (1-c^2 x^2\right )}\right ) \, dx}{2 e}\\ &=\frac {(d+e x)^2 \left (a+b \tanh ^{-1}(c x)\right )^3}{2 e}-\frac {(3 b) \int \frac {\left (c^2 d^2+e^2+2 c^2 d e x\right ) \left (a+b \tanh ^{-1}(c x)\right )^2}{1-c^2 x^2} \, dx}{2 c e}+\frac {(3 b e) \int \left (a+b \tanh ^{-1}(c x)\right )^2 \, dx}{2 c}\\ &=\frac {3 b e x \left (a+b \tanh ^{-1}(c x)\right )^2}{2 c}+\frac {(d+e x)^2 \left (a+b \tanh ^{-1}(c x)\right )^3}{2 e}-\frac {(3 b) \int \left (\frac {c^2 d^2 \left (1+\frac {e^2}{c^2 d^2}\right ) \left (a+b \tanh ^{-1}(c x)\right )^2}{1-c^2 x^2}+\frac {2 c^2 d e x \left (a+b \tanh ^{-1}(c x)\right )^2}{1-c^2 x^2}\right ) \, dx}{2 c e}-\left (3 b^2 e\right ) \int \frac {x \left (a+b \tanh ^{-1}(c x)\right )}{1-c^2 x^2} \, dx\\ &=\frac {3 b e \left (a+b \tanh ^{-1}(c x)\right )^2}{2 c^2}+\frac {3 b e x \left (a+b \tanh ^{-1}(c x)\right )^2}{2 c}+\frac {(d+e x)^2 \left (a+b \tanh ^{-1}(c x)\right )^3}{2 e}-(3 b c d) \int \frac {x \left (a+b \tanh ^{-1}(c x)\right )^2}{1-c^2 x^2} \, dx-\frac {\left (3 b^2 e\right ) \int \frac {a+b \tanh ^{-1}(c x)}{1-c x} \, dx}{c}-\frac {\left (3 b \left (c^2 d^2+e^2\right )\right ) \int \frac {\left (a+b \tanh ^{-1}(c x)\right )^2}{1-c^2 x^2} \, dx}{2 c e}\\ &=\frac {3 b e \left (a+b \tanh ^{-1}(c x)\right )^2}{2 c^2}+\frac {3 b e x \left (a+b \tanh ^{-1}(c x)\right )^2}{2 c}+\frac {d \left (a+b \tanh ^{-1}(c x)\right )^3}{c}-\frac {\left (d^2+\frac {e^2}{c^2}\right ) \left (a+b \tanh ^{-1}(c x)\right )^3}{2 e}+\frac {(d+e x)^2 \left (a+b \tanh ^{-1}(c x)\right )^3}{2 e}-\frac {3 b^2 e \left (a+b \tanh ^{-1}(c x)\right ) \log \left (\frac {2}{1-c x}\right )}{c^2}-(3 b d) \int \frac {\left (a+b \tanh ^{-1}(c x)\right )^2}{1-c x} \, dx+\frac {\left (3 b^3 e\right ) \int \frac {\log \left (\frac {2}{1-c x}\right )}{1-c^2 x^2} \, dx}{c}\\ &=\frac {3 b e \left (a+b \tanh ^{-1}(c x)\right )^2}{2 c^2}+\frac {3 b e x \left (a+b \tanh ^{-1}(c x)\right )^2}{2 c}+\frac {d \left (a+b \tanh ^{-1}(c x)\right )^3}{c}-\frac {\left (d^2+\frac {e^2}{c^2}\right ) \left (a+b \tanh ^{-1}(c x)\right )^3}{2 e}+\frac {(d+e x)^2 \left (a+b \tanh ^{-1}(c x)\right )^3}{2 e}-\frac {3 b^2 e \left (a+b \tanh ^{-1}(c x)\right ) \log \left (\frac {2}{1-c x}\right )}{c^2}-\frac {3 b d \left (a+b \tanh ^{-1}(c x)\right )^2 \log \left (\frac {2}{1-c x}\right )}{c}+\left (6 b^2 d\right ) \int \frac {\left (a+b \tanh ^{-1}(c x)\right ) \log \left (\frac {2}{1-c x}\right )}{1-c^2 x^2} \, dx-\frac {\left (3 b^3 e\right ) \operatorname {Subst}\left (\int \frac {\log (2 x)}{1-2 x} \, dx,x,\frac {1}{1-c x}\right )}{c^2}\\ &=\frac {3 b e \left (a+b \tanh ^{-1}(c x)\right )^2}{2 c^2}+\frac {3 b e x \left (a+b \tanh ^{-1}(c x)\right )^2}{2 c}+\frac {d \left (a+b \tanh ^{-1}(c x)\right )^3}{c}-\frac {\left (d^2+\frac {e^2}{c^2}\right ) \left (a+b \tanh ^{-1}(c x)\right )^3}{2 e}+\frac {(d+e x)^2 \left (a+b \tanh ^{-1}(c x)\right )^3}{2 e}-\frac {3 b^2 e \left (a+b \tanh ^{-1}(c x)\right ) \log \left (\frac {2}{1-c x}\right )}{c^2}-\frac {3 b d \left (a+b \tanh ^{-1}(c x)\right )^2 \log \left (\frac {2}{1-c x}\right )}{c}-\frac {3 b^3 e \text {Li}_2\left (1-\frac {2}{1-c x}\right )}{2 c^2}-\frac {3 b^2 d \left (a+b \tanh ^{-1}(c x)\right ) \text {Li}_2\left (1-\frac {2}{1-c x}\right )}{c}+\left (3 b^3 d\right ) \int \frac {\text {Li}_2\left (1-\frac {2}{1-c x}\right )}{1-c^2 x^2} \, dx\\ &=\frac {3 b e \left (a+b \tanh ^{-1}(c x)\right )^2}{2 c^2}+\frac {3 b e x \left (a+b \tanh ^{-1}(c x)\right )^2}{2 c}+\frac {d \left (a+b \tanh ^{-1}(c x)\right )^3}{c}-\frac {\left (d^2+\frac {e^2}{c^2}\right ) \left (a+b \tanh ^{-1}(c x)\right )^3}{2 e}+\frac {(d+e x)^2 \left (a+b \tanh ^{-1}(c x)\right )^3}{2 e}-\frac {3 b^2 e \left (a+b \tanh ^{-1}(c x)\right ) \log \left (\frac {2}{1-c x}\right )}{c^2}-\frac {3 b d \left (a+b \tanh ^{-1}(c x)\right )^2 \log \left (\frac {2}{1-c x}\right )}{c}-\frac {3 b^3 e \text {Li}_2\left (1-\frac {2}{1-c x}\right )}{2 c^2}-\frac {3 b^2 d \left (a+b \tanh ^{-1}(c x)\right ) \text {Li}_2\left (1-\frac {2}{1-c x}\right )}{c}+\frac {3 b^3 d \text {Li}_3\left (1-\frac {2}{1-c x}\right )}{2 c}\\ \end {align*}
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Mathematica [A] time = 0.75, size = 331, normalized size = 1.36 \[ \frac {2 a^3 c^2 e x^2+6 a^2 b c^2 x \tanh ^{-1}(c x) (2 d+e x)+2 a^2 c x (2 a c d+3 b e)+3 a^2 b (2 c d+e) \log (1-c x)+3 a^2 b (2 c d-e) \log (c x+1)+6 a b^2 e \left (\log \left (1-c^2 x^2\right )+\left (c^2 x^2-1\right ) \tanh ^{-1}(c x)^2+2 c x \tanh ^{-1}(c x)\right )+12 a b^2 c d \left (\text {Li}_2\left (-e^{-2 \tanh ^{-1}(c x)}\right )+\tanh ^{-1}(c x) \left ((c x-1) \tanh ^{-1}(c x)-2 \log \left (e^{-2 \tanh ^{-1}(c x)}+1\right )\right )\right )-2 b^3 e \left (\tanh ^{-1}(c x) \left (\left (1-c^2 x^2\right ) \tanh ^{-1}(c x)^2+(3-3 c x) \tanh ^{-1}(c x)+6 \log \left (e^{-2 \tanh ^{-1}(c x)}+1\right )\right )-3 \text {Li}_2\left (-e^{-2 \tanh ^{-1}(c x)}\right )\right )+4 b^3 c d \left (3 \tanh ^{-1}(c x) \text {Li}_2\left (-e^{-2 \tanh ^{-1}(c x)}\right )+\frac {3}{2} \text {Li}_3\left (-e^{-2 \tanh ^{-1}(c x)}\right )+\tanh ^{-1}(c x)^2 \left ((c x-1) \tanh ^{-1}(c x)-3 \log \left (e^{-2 \tanh ^{-1}(c x)}+1\right )\right )\right )}{4 c^2} \]
Warning: Unable to verify antiderivative.
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fricas [F] time = 0.74, size = 0, normalized size = 0.00 \[ {\rm integral}\left (a^{3} e x + a^{3} d + {\left (b^{3} e x + b^{3} d\right )} \operatorname {artanh}\left (c x\right )^{3} + 3 \, {\left (a b^{2} e x + a b^{2} d\right )} \operatorname {artanh}\left (c x\right )^{2} + 3 \, {\left (a^{2} b e x + a^{2} b d\right )} \operatorname {artanh}\left (c x\right ), x\right ) \]
Verification of antiderivative is not currently implemented for this CAS.
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giac [F] time = 0.00, size = 0, normalized size = 0.00 \[ \int {\left (e x + d\right )} {\left (b \operatorname {artanh}\left (c x\right ) + a\right )}^{3}\,{d x} \]
Verification of antiderivative is not currently implemented for this CAS.
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maple [C] time = 1.25, size = 12404, normalized size = 50.84 \[ \text {output too large to display} \]
Verification of antiderivative is not currently implemented for this CAS.
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maxima [F] time = 0.00, size = 0, normalized size = 0.00 \[ \frac {1}{2} \, a^{3} e x^{2} + \frac {3}{4} \, {\left (2 \, x^{2} \operatorname {artanh}\left (c x\right ) + c {\left (\frac {2 \, x}{c^{2}} - \frac {\log \left (c x + 1\right )}{c^{3}} + \frac {\log \left (c x - 1\right )}{c^{3}}\right )}\right )} a^{2} b e + a^{3} d x + \frac {3 \, {\left (2 \, c x \operatorname {artanh}\left (c x\right ) + \log \left (-c^{2} x^{2} + 1\right )\right )} a^{2} b d}{2 \, c} - \frac {{\left (b^{3} c^{2} e x^{2} + 2 \, b^{3} c^{2} d x - {\left (2 \, c d + e\right )} b^{3}\right )} \log \left (-c x + 1\right )^{3} - 3 \, {\left (2 \, a b^{2} c^{2} e x^{2} + 2 \, {\left (2 \, a b^{2} c^{2} d + b^{3} c e\right )} x + {\left (b^{3} c^{2} e x^{2} + 2 \, b^{3} c^{2} d x + {\left (2 \, c d - e\right )} b^{3}\right )} \log \left (c x + 1\right )\right )} \log \left (-c x + 1\right )^{2}}{16 \, c^{2}} - \int -\frac {{\left (b^{3} c^{2} e x^{2} - b^{3} c d + {\left (c^{2} d - c e\right )} b^{3} x\right )} \log \left (c x + 1\right )^{3} + 6 \, {\left (a b^{2} c^{2} e x^{2} - a b^{2} c d + {\left (c^{2} d - c e\right )} a b^{2} x\right )} \log \left (c x + 1\right )^{2} - 3 \, {\left (2 \, a b^{2} c^{2} e x^{2} + {\left (b^{3} c^{2} e x^{2} - b^{3} c d + {\left (c^{2} d - c e\right )} b^{3} x\right )} \log \left (c x + 1\right )^{2} + 2 \, {\left (2 \, a b^{2} c^{2} d + b^{3} c e\right )} x - {\left (4 \, a b^{2} c d - {\left (2 \, c d - e\right )} b^{3} - {\left (4 \, a b^{2} c^{2} e + b^{3} c^{2} e\right )} x^{2} - 2 \, {\left (b^{3} c^{2} d + 2 \, {\left (c^{2} d - c e\right )} a b^{2}\right )} x\right )} \log \left (c x + 1\right )\right )} \log \left (-c x + 1\right )}{8 \, {\left (c^{2} x - c\right )}}\,{d x} \]
Verification of antiderivative is not currently implemented for this CAS.
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mupad [F] time = 0.00, size = -1, normalized size = -0.00 \[ \int {\left (a+b\,\mathrm {atanh}\left (c\,x\right )\right )}^3\,\left (d+e\,x\right ) \,d x \]
Verification of antiderivative is not currently implemented for this CAS.
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sympy [F] time = 0.00, size = 0, normalized size = 0.00 \[ \int \left (a + b \operatorname {atanh}{\left (c x \right )}\right )^{3} \left (d + e x\right )\, dx \]
Verification of antiderivative is not currently implemented for this CAS.
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